(3x^2+x-5)(2x-7)=

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Solution for (3x^2+x-5)(2x-7)= equation: 


Simplifying
(3x2 + x + -5)(2x + -7) = 0

Reorder the terms:
(-5 + x + 3x2)(2x + -7) = 0

Reorder the terms:
(-5 + x + 3x2)(-7 + 2x) = 0

Multiply (-5 + x + 3x2) * (-7 + 2x)
(-5(-7 + 2x) + x(-7 + 2x) + 3x2 * (-7 + 2x)) = 0
((-7 * -5 + 2x * -5) + x(-7 + 2x) + 3x2 * (-7 + 2x)) = 0
((35 + -10x) + x(-7 + 2x) + 3x2 * (-7 + 2x)) = 0
(35 + -10x + (-7 * x + 2x * x) + 3x2 * (-7 + 2x)) = 0
(35 + -10x + (-7x + 2x2) + 3x2 * (-7 + 2x)) = 0
(35 + -10x + -7x + 2x2 + (-7 * 3x2 + 2x * 3x2)) = 0
(35 + -10x + -7x + 2x2 + (-21x2 + 6x3)) = 0

Combine like terms: -10x + -7x = -17x
(35 + -17x + 2x2 + -21x2 + 6x3) = 0

Combine like terms: 2x2 + -21x2 = -19x2
(35 + -17x + -19x2 + 6x3) = 0

Solving
35 + -17x + -19x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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